I was motivated to do the Math. So here it is, I think... if it was a 7m gap and a, 11m drop, that gives us a hypotenuse of 13.something, which I rounded up to 13.1m to roughly account for their curved travel path. That is 42.9790 feet of travel. h(t) = 42.9790 - 16t2 for finding the amount of time t, traveled in the air. If h(t) is the height of impact, 0, then that gives us a travel time of 1.63896 seconds. Solving for velocity = gravity x time, he was ~roughly~ traveling at about 17.88 mph when he hit the pads. If someone wants to do the weight that was put on his knees at the point of impact, I would like that.